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25x-3000-20x+0.1x^2=1
We move all terms to the left:
25x-3000-20x+0.1x^2-(1)=0
We add all the numbers together, and all the variables
0.1x^2+5x-3001=0
a = 0.1; b = 5; c = -3001;
Δ = b2-4ac
Δ = 52-4·0.1·(-3001)
Δ = 1225.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{1225.4}}{2*0.1}=\frac{-5-\sqrt{1225.4}}{0.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{1225.4}}{2*0.1}=\frac{-5+\sqrt{1225.4}}{0.2} $
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